3y^2+2y+3/4=0

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Solution for 3y^2+2y+3/4=0 equation: 



3y^2+2y+3/4=0

We multiply all the terms by the denominator


3y^2*4+2y*4+3=0

Wy multiply elements

12y^2+8y+3=0

a = 12; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·12·3
Δ = -80
Delta is less than zero, so there is no solution for the equation

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